1948 United States presidential election in Wyoming
http://dbpedia.org/resource/1948_United_States_presidential_election_in_Wyoming an entity of type: Thing
The 1948 United States presidential election in Wyoming took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president. This is the most recent presidential election in which Wyoming voted more Democratic than the national average; the state is now heavily Republican. It would only a support a Democratic presidential nominee one more time, during Lyndon B. Johnson's 1964 landslide. Dewey had previously won the state four years earlier.
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1948 United States presidential election in Wyoming
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1948-11-02
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1948
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Harry S Truman, bw half-length photo portrait, facing front, 1945 .jpg
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The 1948 United States presidential election in Wyoming took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president. Wyoming was won by President Harry S. Truman (D–Missouri), running with the Senate Majority Leader Alben W. Barkley, with 51.62 percent of the popular vote, against the 47th Governor of New York Thomas E. Dewey (R–New York), running with California Governor and future Chief Justice of the United States Earl Warren, with 47.27 percent of the popular vote. This is the most recent presidential election in which Wyoming voted more Democratic than the national average; the state is now heavily Republican. It would only a support a Democratic presidential nominee one more time, during Lyndon B. Johnson's 1964 landslide. Dewey had previously won the state four years earlier.
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1948-11-02
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1948United States presidential electionin Wyoming